NCERT Solutions for Class 12 Physics Chapter 9 Ray Optics Instruments

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Determine refractive index of a slab using traveling microscope. If the candle is moved closer to the mirror, how would the screen have to be moved? Singh raised the same question to her daughter Anuja who explained why plastic lenses were thicker.

The negative sign indicates that the image is inverted and real. If the prism is placed in water refractive index 1.

Ray Optics And Optical Instruments

All the solutions are explained by experienced subject experts of Physics in a detailed manner. If the angle of the prism is 5° and the prism is made of a material of refractive index 1. After travelling through the slab, the first colour to emerge is a blue b green c violet d red Solution: d We know that, when a light ray goes from one medium to other medium, the frequency of light remains constant. Hence, it has highest speed. Therefore, the red colour will emerge first after travelling through the slab. Question: A passenger in an aeroplane shall a never see a rainbow b may see a primary and a secondary rainbow as concentric circles c may see a primary and a secondary rainbow as concentric arcs d shall never see a secondary rainbow Solution: b A passenger sitting in an aeroplane may see a primary and a secondary rainbow like concentric circles. Question: A car is moving with at a constant speed of 60 km h - 1 on a straight road. Looking at the rear view mirror, the driver finds that the car following him at a distance of 100 m and is approaching with a speed of 5 kmh - 1. In order to keep track of the car in the rear, the driver ray optics class 12 ncert pdf to glance alternatively at the rear and side mirror of his car after every 2 s till the other car overtakes. Therefore, the speed of the approaching car would appear ray optics class 12 ncert pdf increase as the distance between the cars decreases in the side mirror. Question: Between the primary and secondary rainbows, there is a dark band known as Alexandar's dark band. This is because a light scattered into this region interfere destructively b there is no light scattered into this region c light is absorbed in this region d angle made at the eye by the scattered rays with respect to the incident light of the sun lies between approximately 42° and 50° Solution: a, d Alexandar's dark band lies between the primary and secondary rainbows, forms because the light scattered into this region interfere destructively. With respect to the incident light, the primary and secondary rainbows subtends an angle nearly 41° to 42° and 51° to 54° at observer's eye respectively. Hence, the scattered ray with respect to the incident light of the sun lies between approximately 42° and 50°.

Derive the expression for the instantaneous value of the emf induced in the coil. However, we shall restrict our discussion to the special case of curved surfaces, that is, spherical surfaces. A parallel beam of light is incident on a face of the prism. Draw the geometrical shape of the wave fronts when. Is the image erect or inverted? If the prism is placed in water refractive index 1. Question 10 : What is the focal length of a convex lens of focal length 30 cm in contact with a concave lens of focal length 20 cm?